Herman Venter
5e215dbca2
The code to print out the result of the expression following the = command has moved from inside the resulting eval block, to outside it in the debugger code itself. Hence, if the eval block fails, the value of $_ now prints out and this is confusion because it is the value that a previous = command put in there. With this change the eval block first unsets $_, so that the subsequent print value code will do nothing in the case of a failure. Differential Revision: D944120
17 linhas
231 B
PHP
17 linhas
231 B
PHP
<?php
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function foo($x) {
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return $x + 1;
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}
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function throwSomething() {
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global $_;
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throw new Exception($_);
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}
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function printSomething() {
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global $_;
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echo $_;
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return "also returned something";
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}
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